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Sketch the graph of the polar equation r=404+10cos⁡θr = \frac { 40 } { 4 + 10 \cos \theta }


A) Sketch the graph of the polar equation r = \frac { 40 } { 4 + 10 \cos \theta } A) B) C) D)
B) Sketch the graph of the polar equation r = \frac { 40 } { 4 + 10 \cos \theta } A) B) C) D)
C) Sketch the graph of the polar equation r = \frac { 40 } { 4 + 10 \cos \theta } A) B) C) D)
D) Sketch the graph of the polar equation r = \frac { 40 } { 4 + 10 \cos \theta } A) B) C) D)

E) None of the above
F) B) and D)

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Find an equation for the set of points in an xy-plane that are equidistant from the point P and the line l. P(−6,3) ,l:x=−2P ( - 6,3 ) , l : x = - 2


A) (x−3) 2=−8(y+4) ( x - 3 ) ^ { 2 } = - 8 ( y + 4 )
B) (y−3) 2=−8(y+4) ( y - 3 ) ^ { 2 } = - 8 ( y + 4 )
C) (y+3) 2=−8(y+4) ( y + 3 ) ^ { 2 } = - 8 ( y + 4 )
D) (y−3) =−8(y+4) 2( y - 3 ) = - 8 ( y + 4 ) ^ { 2 }
E) (y−3) 2=(y+4) ( y - 3 ) ^ { 2 } = ( y + 4 )

F) C) and E)
G) D) and E)

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Identify the graph of the equation as a parabola (with vertical or horizontal axis) , circle, ellipse, or hyperbola. 13(x+3) =y2\frac { 1 } { 3 } ( x + 3 ) = y ^ { 2 }


A) Parabola with vertical axis
B) Hyperbola
C) Ellipse
D) Parabola with horizontal axis
E) Circle

F) A) and E)
G) A) and D)

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Find an equation for the ellipse shown in the figure. Find an equation for the ellipse shown in the figure. A) \frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1 B) \frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 25 } = 1 C) \frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 25 } = 1 D) \frac { ( x + 1 ) ^ { 2 } } { 25 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1 E) \frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1


A) (x−1) 225+(y+1) 24=1\frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1
B) (x+1) 24+(y+1) 225=1\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 25 } = 1
C) (x−1) 24+(y+1) 225=1\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 25 } = 1
D) (x+1) 225+(y−1) 24=1\frac { ( x + 1 ) ^ { 2 } } { 25 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1
E) (x−1) 225+(y−1) 24=1\frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1

F) A) and B)
G) C) and D)

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Find a parametrization that gives the same graph as the given equation. y=ln⁡x5y = \ln x ^ { 5 }


A) x=t3,y=t15x = t ^ { 3 } , y = t ^ { 15 }
B) x=et,y=t5x = e ^ { t } , y = \frac { t } { 5 }
C) x=t5,y=etx = \frac { t } { 5 } , y = e ^ { t }
D) x=t15,y=t3x = t ^ { 15 } , y = t ^ { 3 }
E) x=et,y=5tx = e ^ { t } , y = 5 t

F) C) and D)
G) B) and E)

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