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Choose the one alternative that best completes the statement or answers the question. - 16(p/2) 16 ( \mathrm { p } / 2 ) (12) p\left( \frac { 1 } { 2 } \right) ^ { p }(12) p\left( \frac { 1 } { 2 } \right) ^ { p }


A) 4P4 \mathrm { P }
B) (4p) (3/2) p+1\left( \frac { 4 } { p } \right) ^ { ( 3 / 2 ) p + 1 }
C) 1
D) cannot be simplified

E) B) and D)
F) B) and C)

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Solve for x. - e(x2+9) \mathrm { e } ^ { \left( \mathrm { x } ^ { 2 } + 9 \right) }e(6x) e ^ { ( 6 x ) } = 1


A) x = 0
B) x = ln 12\frac { 1 } { 2 }
C) x = -3
D) x = ± 3\sqrt { 3 }

E) A) and D)
F) None of the above

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Simplify. -( exe ^ { x } + ex\mathrm { e } ^ { - \mathrm { x } } )( exe ^ { x } - ex\mathrm { e } ^ { - \mathrm { x } } )Enter your answer exactly as eaebe ^ { a } - e ^ { b }

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Choose the one alternative that best completes the statement or answers the question. -( t2t ^ { 2 } ) x) ^ { x } ∙ ( t4t^4 ) x) ^ { x } ∙ ( t1/3t ^{1 / 3} ) x) ^ { x }


A) ( t19/3xt ^{19 / 3 x} ) 3x) ^ { 3 x }
B) t(8/3) xt ^{( 8 / 3 ) x}
C) ((t19/3) x\left((t 19 / 3) ^{x}\right.
D) ( t8t ^ { 8 } ) x/3) ^ { x / 3 }

E) B) and D)
F) None of the above

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The expression may be factored as shown. Find the missing factor. 52+h5 ^ { 2 } + h = 25(  The expression may be factored as shown. Find the missing factor.  5 ^ { 2 } + h  = 25(   ) Enter your answer as  5 ^a  . ) Enter your answer as 5a5 ^a .

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Solve for x. -2 - ln(x + 3) = ln 4


A) x = ln 4 - 1
B) x = 2e
C) x = -3
D) x = 14\frac { 1 } { 4 } e2e ^ { 2 } - 3

E) A) and D)
F) B) and C)

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ln x2x ^ { 2 } + (ln x )2)^2 = 0 Enter your answer exactly as x = a, b (a < b).

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Differentiate. -(6 e2x\mathrm { e } ^ { 2 x } - x ) 3) ^ { 3 }


A) 3(12 xe2x1x e ^ { 2 x - 1 } - 1 ) 2) ^2
B) 3(6 e2x\mathrm { e } ^ { 2 x } - x ) 2) ^2 (12 e2x\mathrm { e } ^ { 2 x } - 1)
C) 3(12 exe ^ { x } - 1 ) 2) ^2
D) 3(6 e2x\mathrm { e } ^ { 2 x } - x ) 2) ^2 (12 e2x\mathrm { e } ^ { 2 x } )

E) None of the above
F) A) and B)

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Use logarithmic differentiation to differentiate. -ln [xexx2+1]\left[ \frac { \sqrt { \mathrm { xe } ^ { x } } } { \mathrm { x } ^ { 2 } + 1 } \right] at x = 1 Enter just a reduced fraction of form ab\frac { a } { b } .

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Estimate the slope of the curve y=exy = e ^ { x } at x = 0.


A) 1
B) 0
C) e
D) exe ^ { x }
E) none of these

F) A) and B)
G) C) and D)

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Solve for x. -ln(x + 1) = 2 + ln x


A) e2e ^ { 2 } - 1
B) e + 1
C) 1e21\frac { 1 } { e ^ { 2 } - 1 }
D) e - 1
E) none of these

F) A) and E)
G) A) and C)

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Solve for x: 35x3 ^ { 5 } x3x23 x ^ { 2 }333 ^ { 3 } = 333 - 3 . Enter your answer exactly as x = a, b ( a < b).

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Which of the following properties are true of the graph of y = 10 e2x\mathrm { e } ^ { 2 x } ? (I) It is concave up. (II) The y-intercept is (0, 2) . (III) It has a minimum at x = 0. (IV) y is positive for x ≥ 0 and negative for x < 0.


A) I only
B) I and III
C) I and II
D) III and IV

E) A) and B)
F) C) and D)

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Solve for x. -ln(1 + x2x ^ { 2 } ) = 2. Enter your answer exactly as just ± ea±b\sqrt { \mathrm { e } ^ { a } \pm b } (a, b integers).

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f(x) = ex+1ex1\frac { e ^ { x } + 1 } { e ^ { x } - 1 } Enter your answer exactly as just P(ex)(Q(ex))n\frac { \mathrm { P } \left( \mathrm { e } ^ { \mathrm { x } } \right) } { \left( \mathrm { Q } \left( \mathrm { e } ^ { \mathrm { x } } \right) \right) ^ { \mathrm { n } } } where P and Q are polynomials in exe ^ { x } in standard form.

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Differentiate. - e3xe ^ { 3 x }


A) 3x
B) e3xe ^ { 3 x }
C) 3 e3xe ^ { 3 x }
D) 13\frac { 1 } { 3 } e3xe ^ { 3 x }

E) A) and B)
F) A) and C)

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Differentiate. -(ln( x2x ^ { 2 } + 2) ) 3) ^ { 3 }


A) e (1x2+2) 2\left( \frac { 1 } { x ^ { 2 } + 2 } \right) ^ { 2 } ∙ 2x
B) 3(ln(2x) ) 2) ^ { 2 }
C) 6xx2+2\frac { 6 x } { x ^ { 2 } + 2 } (ln( x2x ^ { 2 } + 2) ) 2) 2
D) 1(ln(x2+2) ) 3\frac { 1 } { \left( \ln \left( x ^ { 2 } + 2 \right) \right) ^ { 3 } } ∙ 2x

E) None of the above
F) B) and C)

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Differentiate. -ln x+2x1\frac { x + 2 } { x - 1 }


A) 3x(x+2) (x1) \frac { 3 x } { ( x + 2 ) ( x - 1 ) }
B) 1x+2\frac { 1 } { x + 2 } - 1x1\frac { 1 } { x - 1 }
C) (x1) (x+2) (x+3) \frac { ( x - 1 ) } { ( x + 2 ) ( x + 3 ) }
D) x1x+2\frac { x - 1 } { x + 2 }
E) none of these

F) A) and C)
G) None of the above

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ln (1ex)\left( \frac { 1 } { \mathrm { e } ^ { \mathrm { x } } } \right) Enter just a standard polynomial in x.

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f(x) = lnxex\frac { \ln x } { \mathrm { e } ^ { \mathrm { x } } } at x = 1 Enter your answer as just eae ^ { a } .

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